本人的畢業設計：關于UG的二次開發運用（GRIP語言編程）

fewofj

下面是關于凸輪的一個運動軌跡的編程，只要把程序導入到UG中就可以實現凸輪的運轉，還可以修改程序中各個凸輪的參數來實現各種凸輪的運轉。組合運動規律
3 D+ T/ ~$ Q. t9 m5 }1 cENTITY/pt(360),spln(4),PT1,CR1,CR2,ext
NUMBER/J(360),S(360),X(360),Y(360),i,m,e,n
" M/ f3 O  O; \) k7 b0 l5 w; ^% \DATA/i,1,m,1,e,1,n,1  $$賦值
l30:
. A! ^1 v0 `, K0 SPARAM/'凸輪參數',$
'升程（h）',h,$
2 ^0 B6 k! G- t) f; t! z( k: u'基圓半徑（R0）',R0,$
'滾子半徑（Rr）',Rr,$
'推程轉角（Angle1）',Angle1,$
+ ?: H3 @* H" i% M' r'遠休止角（Angle2）',Angle2,$
3 P+ t$ P9 `6 G& g" K% [7 x; g'回程轉角（Angle3）',Angle3,$
'近休止角（Angle4）',Angle4,$
  z7 F' e$ r0 s- \respond
JUMP/l30:,stop:,,respond
- W6 n: x5 m( v0 c( e5 W% TMESSG/'您已輸入完參數！'
l00:
CHOOSE/'選擇推程運動規律',$
'一次多項式推程','二次多項式推程','五次多項式推程',$
'簡諧運動推程','擺線運動推程',$
DEFLT,1,respond
5 x3 ~7 ]7 e2 H5 `" \1 uJUMP/l00:,stop:,,,lab1:,lab2:,lab3:,lab4:,lab5:,respond
l20:
5 a5 m: z' ?* Q  w4 {CHOOSE/'選擇回程運動規律',$
'一次多項式回程','二次多項式回程','五次多項式回程',$
'簡諧運動回程','擺線運動回程',$
DEFLT,1,respond
JUMP/l20:,stop:,,,lab6:,lab7:,lab8:,lab9:,lab10:,respond
lab1:
MESSG/'一次多項式推程'
* ~$ s5 r! R/ Y$ ~5 qLAA:
IFTHEN/i<Angle1+2
* U+ B: F) G1 s4 ]J(i)=i-1
) b% B& s# w& h2 G7 n5 \* OS(i)=h*J(i)/Angle1
X(i)=(R0+S(i))*cosf(J(i))
Y(i)=(R0+S(i))*sinf(J(i))
Z=0
. A( O4 Y3 h1 V+ J! V* R) y" cpt(i)=POINT/X(i),Y(i),Z
i=i+1
4 W& x2 A8 z1 L- t1 tJUMP/LAA:
) l+ D! I* n3 c+ Y. DENDIF
) z* `! s! r. Z2 k: Gspln(1)=SPLINE/pt(1..Angle1+1)
7 @; {+ Z7 u: s0 ?/ G2 ^1 S* R- @2 f) qDELETE/pt(1..Angle1+1)
JUMP/l20:
lab2:
: E2 F8 S: `1 J. X; T9 Z. FMESSG/'二次多項式推程'
* Z) h" w0 }; w* o, c- \! F$$推程等加速階段
LBB:
2 d% L, q  ?+ A+ _' _IFTHEN/i<Angle1/2+2
J(i)=i-1
& P( I. S) r( f- D- o6 Q% ~3 Y1 ~S(i)=2*h*J(i)*J(i)/(Angle1*Angle1)
; c8 u1 Y- ~6 L3 hX(i)=(R0+S(i))*cosf(J(i))
) c- K. g+ a% d$ f7 m8 q6 NY(i)=(R0+S(i))*sinf(J(i))
0 l7 A9 ^5 X) d: q  A. ~! ~Z=0
5 K$ z2 T; d5 qpt(i)=POINT/X(i),Y(i),Z
; ]( o& U% t% o5 B% bi=i+1
, V; Y$ ], P  r) ~JUMP/LBB:
ENDIF
; c2 P* l9 q2 _9 @spln(1)=SPLINE/pt(1..Angle1/2+1)
! k( n) A. e) f9 r" ]DELETE/pt(1..Angle1/2+1)
) Y7 C& o: n% O  j$$推程等減速階段
LCC:
IFTHEN/e<Angle1/2+2
5 H9 p( t+ }' Y9 VJ(e)=e+Angle1/2-1
# _: H) Y) J* V, g+ L4 G2 IS(e)=h-2*h*(Angle1-J(e))*(Angle1-J(e))/(Angle1*Angle1)
+ ]; A2 W2 m: f! Z; X  M7 s5 q1 wX(e)=(R0+S(e))*cosf(J(e))
Y(e)=(R0+S(e))*sinf(J(e))
" U, g$ w3 y3 L% \4 B! GZ=0
pt(e)=POINT/X(e),Y(e),Z
e=e+1
JUMP/LCC:
ENDIF
0 B) v/ A* y9 b; ]( D' B1 a2 i- Nspln(2)=SPLINE/pt(1..Angle1/2+1)
& Q& }: m# x$ G2 mDELETE/pt(1..Angle1/2+1)
+ z# D0 k' w% Z' U# l4 LJUMP/l20:
lab3:
6 j0 _! X7 @. X0 `7 yMESSG/'五次多項式推程'
2 }" u" \3 S2 v! |8 W( nLDD:
IFTHEN/i<Angle1+2
% ?" P4 ?6 I! B% n- bJ(i)=i-1
Q=J(i)/Angle1
5 p! g* M; ]$ [; ~6 bS(i)=h*(10*Q*Q*Q-15*Q*Q*Q*Q+6*Q*Q*Q*Q*Q)
X(i)=(R0+S(i))*cosf(J(i))
Y(i)=(R0+S(i))*sinf(J(i))
Z=0
pt(i)=POINT/X(i),Y(i),Z
' G# f% I, H& P' u# h2 si=i+1
4 C6 T; P9 [# y' k$ S; Y* l7 Y$ dJUMP/LDD:
ENDIF
spln(1)=SPLINE/pt(1..Angle1+1)
DELETE/pt(1..Angle1+1)
JUMP/l20:
lab4:
MESSG/'簡諧運動推程'
  A" Q3 M/ I8 f: S! @/ MLEE:
IFTHEN/i<Angle1+2
# T- m7 Y3 M- yJ(i)=i-1
S(i)=h*(1-cosf(180*J(i)/Angle1))/2
X(i)=(R0+S(i))*cosf(J(i))
Y(i)=(R0+S(i))*sinf(J(i))
( g) K4 d7 R/ E; x) q7 ^; o0 LZ=0
4 F8 F7 v/ ^  X0 {' ?pt(i)=POINT/X(i),Y(i),Z
i=i+1
JUMP/LEE:
ENDIF
& R  j" Q( a( Nspln(1)=SPLINE/pt(1..Angle1+1)
0 y# A3 Z8 W; z) F8 wDELETE/pt(1..Angle1+1)
JUMP/l20:
. l8 O- C+ @. Y4 z7 h3 klab5:
" M0 g( Z9 w2 }% M/ ~! z2 d& RMESSG/'擺線運動推程'
1 F$ [/ |# v! O6 gLFF:
IFTHEN/i<Angle1+2
J(i)=i-1
' @* `5 F2 `, m# mS(i)=h*(J(i)/Angle1-sinf(360*J(i)/Angle1)/6.2832)
X(i)=(R0+S(i))*cosf(J(i))
7 J2 N# |; K4 nY(i)=(R0+S(i))*sinf(J(i))
Z=0
6 ~' u+ g$ U- X6 J8 xpt(i)=POINT/X(i),Y(i),Z
i=i+1
JUMP/LFF:
9 O0 k6 P9 l4 z$ f" Y( c; ~ENDIF
1 r" F9 P0 @! L. Y& Q/ f3 I% J7 Espln(1)=SPLINE/pt(1..Angle1+1)
DELETE/pt(1..Angle1+1)
JUMP/l20:
lab6:
MESSG/'一次多項式回程'
LHH:
) q6 r9 u/ V- h0 b4 v; RIFTHEN/m<Angle3+2
: z0 v9 v" ?- KJ(m)=m+Angle1+Angle2-1
S(m)=h-h*(J(m)-Angle1-Angle2)/Angle3
, S' |4 U3 \$ R$ ZX(m)=(R0+S(m))*cosf(J(m))
" j% M' c7 i$ a, a/ X3 ~Y(m)=(R0+S(m))*sinf(J(m))
; P2 j: l( W* h. e+ X; C1 g* OZ=0
pt(m)=POINT/X(m),Y(m),Z
m=m+1
JUMP/LHH:
ENDIF
spln(2)=SPLINE/pt(1..Angle3+1)
DELETE/pt(1..Angle3+1)
JUMP/l40:
7 S' t( o- E+ X4 q7 P7 O4 blab7:
MESSG/'二次多項式回程'
$$回程等減速階段
5 \# h7 R; ?6 Q; XLII:
% D( ^% E$ C2 Q: VIFTHEN/m<Angle3/2+2
J(m)=m+Angle1+Angle2-1
+ ^8 k* J. E; G  i4 iS(m)=h-2*h*(J(m)-Angle1-Angle2)*(J(m)-Angle1-Angle2)/(Angle3*Angle3)
# d# {4 }  C! c, v0 ~' sX(m)=(R0+S(m))*cosf(J(m))
Y(m)=(R0+S(m))*sinf(J(m))
Z=0
pt(m)=POINT/X(m),Y(m),Z
8 x8 O! E" I) M  ^1 _m=m+1
JUMP/LII:
; f! G/ Z  @! ~* gENDIF
spln(3)=SPLINE/pt(1..Angle3/2+1)
DELETE/pt(1..Angle3/2+1)
$$回程等加速階段
. X; X  Q3 ~6 J# \4 jLKK:
1 u0 e, B( O0 N3 n4 w4 [, vIFTHEN/n<Angle3/2+2
J(n)=n+Angle1+Angle2+Angle3/2-1
' \+ e. l; C, H5 cQ=Angle1+Angle2+Angle3
S(n)=2*h*(Q-J(n))*(Q-J(n))/(Angle3*Angle3)
4 y  u- V$ y. ?6 L, a1 K* ]X(n)=(R0+S(n))*cosf(J(n))
$ y0 o+ f  [4 V6 UY(n)=(R0+S(n))*sinf(J(n))
& R( h; U$ o8 ~  I1 f, S! w# m* [' fZ=0
pt(n)=POINT/X(n),Y(n),Z
n=n+1
JUMP/LKK:
ENDIF
+ W$ i8 h# E7 }1 e/ `4 o: W' uspln(4)=SPLINE/pt(1..Angle3/2+1)
! W7 E% Y- I" O5 j: HDELETE/pt(1..Angle3/2+1)
( A( J- B; x, `: cJUMP/l40:
lab8:
MESSG/'五次多項式回程'
, S: e. c" ?5 U. cLRR:
! P% v# p' t& W  sIFTHEN/m<Angle3+2
J(m)=m+Angle1+Angle2-1
W=(J(m)-Angle1-Angle2)/Angle3
S(m)=h-h*(10*W*W*W-15*W*W*W*W+6*W*W*W*W*W)
; t6 c, Y; h$ v5 P+ _X(m)=(R0+S(m))*cosf(J(m))
. A( l6 v( x, JY(m)=(R0+S(m))*sinf(J(m))
2 [: s9 f7 W) g1 P9 x9 AZ=0
- b; F& y/ k$ C! fpt(m)=POINT/X(m),Y(m),Z
m=m+1
0 M6 H9 w( M" ?+ IJUMP/LRR:
& p: a3 r* x/ L1 w0 N% nENDIF
! t# z2 N5 n4 kspln(2)=SPLINE/pt(1..Angle3+1)
, G( k0 ^1 c# L3 ~& jDELETE/pt(1..Angle3+1)
JUMP/l40:
lab9:
MESSG/'簡諧運動回程'
LWW:
4 V% c, q9 j4 q% u0 l. t7 tIFTHEN/m<Angle3+2
J(m)=m+Angle1+Angle2-1
S(m)=h*(1+cosf(180*(J(m)-Angle1-Angle2)/Angle3))/2
X(m)=(R0+S(m))*cosf(J(m))
6 u9 Z( B; y8 WY(m)=(R0+S(m))*sinf(J(m))
8 ?, g+ s( j  n7 N7 I9 {Z=0
- ~* U2 K8 D( F5 i; jpt(m)=POINT/X(m),Y(m),Z
m=m+1
JUMP/LWW:
ENDIF
( q4 Y+ |8 p& q7 p% f5 Dspln(2)=SPLINE/pt(1..Angle3+1)
! X" g( b1 H9 f' TDELETE/pt(1..Angle3+1)
4 }. I" A. _" T1 yJUMP/l40:
* }' M7 g, C9 U5 e, ~. {lab10:
MESSG/'擺線運動回程'
& a- @0 }8 X6 G, {LQQ:
IFTHEN/m<Angle3+2
J(m)=m+Angle1+Angle2-1
A=J(m)-Angle1-Angle2
. s; x8 Z  r% D, j. ?S(m)=h*(1-A/Angle3+sinf(360*A/Angle3)/6.2832)
! a6 B9 z" F! n4 aX(m)=(R0+S(m))*cosf(J(m))
Y(m)=(R0+S(m))*sinf(J(m))
# ]! Z' g; i! n6 Y( r/ t' rZ=0
pt(m)=POINT/X(m),Y(m),Z
+ d4 ?9 M/ r# M# @0 A) l! Tm=m+1
JUMP/LQQ:
2 Q$ h9 V5 i: J/ C" `9 @* ZENDIF
spln(2)=SPLINE/pt(1..Angle3+1)
5 L, U1 Z+ M: D/ Q/ WDELETE/pt(1..Angle3+1)
1 M4 X* {: e- t3 QJUMP/l40:
5 j$ u4 o! H( C3 O' Q' _& fl40:
$$遠休止角
4 n. c' T1 B0 }3 jPT1=POINT/0,0
CR1=CIRCLE/CENTER,PT1,RADIUS,R0+h,START,Angle1,END,Angle1+Angle2
+ e; R; g, ^9 o: F4 G$$近休止角
CR2=CIRCLE/CENTER,PT1,RADIUS,R0,START,Angle1+Angle2+Angle3,END,0
JUMP/stop:
0 i+ p& S* U4 I! e1 r# i) zstop:
halt
$ o" X. d( A8 ~) A. e" m% |* D: i

: c5 x6 E* U/ h7 x& `- a& Y好多圖片不能上傳，如有需要的話。把郵箱給我，我可以發給他
, b: Q* Q! @3 |7 ^

78273928

13793371086@163.com    不勝感激   

fewofj

回復 78273928 的帖子
; a) A6 X" D! e0 e" f$ y+ r- H
馬上發給你。 如果收不到可以QQ聯系我：532131146

78273928

回復 fewofj 的帖子

* ?3 T, c# b+ o" Y0 m% {+ ], }謝謝 收到了  學習一下

xiaowuzh

回復 fewofj 的帖子
, R8 O. Z. B- U- w
樓主我郵箱的xiaowuzhi@126.com。發給我一份吧，謝謝。
: \' X# D- X0 i+ y7 D

zaq8577

謝謝，正想了解一下 zaq8577@163.com

holland930

799350380@qq.com  不勝感激 謝謝！